A vacuum residue of Conradson carbon wt. 16% CCR is fed into delayed coker at rate of 100,000 lb./ hr., of API=9 and with sulfur content of 3 wt. %. Find the amount of yield (Ib/hr) and their sulfur...


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A vacuum residue of Conradson carbon wt. 16% CCR is fed into delayed<br>coker at rate of 100,000 lb./ hr., of API=9 and with sulfur content of 3 wt. %. Find<br>the amount of yield (Ib/hr) and their sulfur content. Calculate yield of liquid<br>Sulfur distribution as follow:<br>|LGO<br>15.4<br>Products<br>| LN<br>HN<br>HGO<br>19.6<br>30<br>Gas<br>Coke<br>S (wt. %)<br>| 30<br>1.7<br>3.3<br>Gas(C, )wt% = 7.8 +0.144 x (wt% CCR)<br>Naphtha wt% = 11.29 + 0.343 x (wt% CCR)<br>Coke wt% = 1.6 x (wt% CCR)<br>Gas oil wt% = 100 – Gas wt% – Naphtha wt% – Coke wt%<br>

Extracted text: A vacuum residue of Conradson carbon wt. 16% CCR is fed into delayed coker at rate of 100,000 lb./ hr., of API=9 and with sulfur content of 3 wt. %. Find the amount of yield (Ib/hr) and their sulfur content. Calculate yield of liquid Sulfur distribution as follow: |LGO 15.4 Products | LN HN HGO 19.6 30 Gas Coke S (wt. %) | 30 1.7 3.3 Gas(C, )wt% = 7.8 +0.144 x (wt% CCR) Naphtha wt% = 11.29 + 0.343 x (wt% CCR) Coke wt% = 1.6 x (wt% CCR) Gas oil wt% = 100 – Gas wt% – Naphtha wt% – Coke wt%

Jun 07, 2022
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