A television station sells advertising in 15-, 30-, 60-, 90- and 120-minute blocks. The distribution of sales for one 24-hour day is: 1. Length in seconds 15 30 60 90 120 Probability 0.134 0.786 0.053...


A television station sells advertising in 15,30,60,90,120 minute blocks. The distribution of sales for one 24-hour day is:


Length in seconds: 15 30 60 90 120


Probability: .134 0.786 0.053 0.006 .023 find the mean variance and standard deviation of the probability


A television station sells advertising in 15-, 30-, 60-, 90- and 120-minute blocks. The distribution<br>of sales for one 24-hour day is:<br>1.<br>Length in seconds<br>15<br>30<br>60<br>90<br>120<br>Probability<br>0.134<br>0.786<br>0.053<br>0.006<br>0.023<br>Find the mean, variance and standard deviation of the probability distribution.<br>

Extracted text: A television station sells advertising in 15-, 30-, 60-, 90- and 120-minute blocks. The distribution of sales for one 24-hour day is: 1. Length in seconds 15 30 60 90 120 Probability 0.134 0.786 0.053 0.006 0.023 Find the mean, variance and standard deviation of the probability distribution.

Jun 10, 2022
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