A system has two different failure types: type 1 and type 2. After a type i-failure the system is said to be in failure state i ; i = 1, 2. The time L i to a type i-failure has an exponential...


A system has two different failure types: type 1 and type 2. After a type i-failure the system is said to be in failure state i ; i = 1, 2. The time Li
to a type i-failure has an exponential distribution with parameter


Thus, if at time t = 0 a new system starts working, the time to its first failure is


The random variables L1
and L2
are assumed to be independent. After a type 1-fai-lure, the system is switched from failure state 1 into failure state 2. The respective mean sojourn times of the system in states 1 and 2 are μ1
and μ2. When in state 2, the system is being renewed. Thus, μ1
is the mean switching time and μ2
the mean renewal time. A renewed system immediately starts working, i.e. the system makes a transition from state 2 to state 0 with probability 1. This process continues to infinity. (For motivation, see example 5.7).


(1) Describe the system behaviour by a semi-Markov chain and draw the transition graph of the embedded discrete-time Markov chain.


(2) Determine the stationary probabilities of the system in the states 0, 1, and 2.



May 06, 2022
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