A solid truncated cone is subject to an axial force P as shown. The exact elongation is d = PL/ (2pc²E). Replace the cone by n equal thickness circular cylinders and derive the expression as a...


A solid truncated cone is subject to an axial force P as shown.<br>The exact elongation is d = PL/ (2pc²E). Replace the cone by<br>n equal thickness circular cylinders and derive the<br>expression as a function of n, P, L, C, E. draw a graph<br>showing variation in elongation d with respect to n values.<br>Take n from 1 to 100. Given that the P = 1 kip, L = 12<br>inch, C= 4 inch, E = 30x10° psi.<br>B<br>2c<br>

Extracted text: A solid truncated cone is subject to an axial force P as shown. The exact elongation is d = PL/ (2pc²E). Replace the cone by n equal thickness circular cylinders and derive the expression as a function of n, P, L, C, E. draw a graph showing variation in elongation d with respect to n values. Take n from 1 to 100. Given that the P = 1 kip, L = 12 inch, C= 4 inch, E = 30x10° psi. B 2c

Jun 08, 2022
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