Given 3 questions are subbarts. Please give me all right solutions with clear calculations
Extracted text: A simple curve with tangents AV and VE have azimuth of 260°48' and 285°40' respectively. Point B is taken along AV and C along VE. The azimuth and distance of BC are 272 16' and 61.22 m respectively. The degree of curve is 5°. The stationing of point B is 8 + 126.3. 1. Determine the radius of the simple curve. b a. 184.99 m b. 229.18 m c. 314.67 m d. 287.25 m 2. Determine the length of curve. a. 99.47 m b. 85.45 m c. 51.93 m d. 79.12 m 3. Determine the stationing of PT. a. 8 + 155.21 b. 8 + 208.98 c. 8 + 311.63 d. 8 + 194.47