A random sample of 4040 adults with no children under the age of 18 years results in a mean daily leisure time of XXXXXXXXXX ​hours, with a standard deviation of XXXXXXXXXX hours. A random sample of...




A random sample of
4040

adults with no children under the age of 18 years results in a mean daily leisure time of
5.135.13

​hours, with a standard deviation of
2.462.46

hours. A random sample of
4040

adults with children under the age of 18 results in a mean daily leisure time of
4.254.25

​hours, with a standard deviation of
1.711.71

hours. Construct and interpret a
9090​%

confidence interval for the mean difference in leisure time between adults with no children and adults with children
left parenthesis mu 1 minus mu 2 right parenthesisμ1−μ2.






Let
mu 1μ1

represent the mean leisure hours of adults with no children under the age of 18 and
mu 2μ2

represent the mean leisure hours of adults with children under the age of 18.


The 90​%confidence interval for
left parenthesis mu 1 minus mu 2 right parenthesisμ1−μ2

is the range from

hours to

hours.

​(Round to two decimal places as​ needed.)




Jun 09, 2022
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