A publisher wants to estimate the mean length of time (in minutes) all adults spend reading newspapers. To determine this estimate, the publisher takes a random sample of 15 people and obtains the...


A publisher wants to estimate the mean length of time (in minutes) all adults spend reading newspapers.<br>To determine this estimate, the publisher takes a random sample of 15 people and obtains the results<br>below. From past studies, the publisher assumes o is 1.5 minutes and that the population of times is<br>normally distributed.<br>7 7<br>10<br>8<br>6<br>9 9<br>9.<br>11<br>6 7 6 9 7 9<br>Construct the 90% and 99% confidence intervals for the population mean. Which interval is wider? If<br>convenient, use technology to construct the confidence intervals.<br>The 90% confidence interval is (<br>). (Round to one decimal place as needed.)<br>

Extracted text: A publisher wants to estimate the mean length of time (in minutes) all adults spend reading newspapers. To determine this estimate, the publisher takes a random sample of 15 people and obtains the results below. From past studies, the publisher assumes o is 1.5 minutes and that the population of times is normally distributed. 7 7 10 8 6 9 9 9. 11 6 7 6 9 7 9 Construct the 90% and 99% confidence intervals for the population mean. Which interval is wider? If convenient, use technology to construct the confidence intervals. The 90% confidence interval is ( ). (Round to one decimal place as needed.)

Jun 02, 2022
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