A publisher wants to estimate the mean length of time (in minutes) all adults spend reading newspapers. To determine this estimate, the publisher takes a random sample of 15 people and obtains the...


A publisher wants to estimate the mean length of time (in minutes) all adults spend reading newspapers. To determine this estimate, the publisher takes a random sample of 15 people and obtains the results below. From past studies, the<br>publisher assumes a is 1.8 minutes and that the population of times is normaly distributed.<br>8.<br>11<br>11<br>10<br>7<br>10<br>10<br>12<br>6<br>11<br>Construct the 90% and 99% confidence intervals for the population mean. Which interval is wider? If convenient, use technology to construct the confidence intervals.<br>The 90% confidence interval is OO). (Round to one decimal place as needed.)<br>

Extracted text: A publisher wants to estimate the mean length of time (in minutes) all adults spend reading newspapers. To determine this estimate, the publisher takes a random sample of 15 people and obtains the results below. From past studies, the publisher assumes a is 1.8 minutes and that the population of times is normaly distributed. 8. 11 11 10 7 10 10 12 6 11 Construct the 90% and 99% confidence intervals for the population mean. Which interval is wider? If convenient, use technology to construct the confidence intervals. The 90% confidence interval is OO). (Round to one decimal place as needed.)

Jun 02, 2022
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