A popular social media platform has begun offering stock shares to the public. In the past 2 years, the price of the stock has generally increased. An investment specialist gathers data on the stock...


A popular social media platform has begun offering<br>stock shares to the public. In the past 2 years, the<br>price of the stock has generally increased. An<br>investment specialist gathers data on the stock price<br>over the past 2 years and proppses two models for<br>estimating the growth of the steck, as shown in the<br>scatterplots.<br>Based on the scatterplots, which type of model is<br>most suitable for estimating the stock price?<br>O A power model is suitable because the scatterplot<br>of log(weeks) against log(stock price) shows a<br>curved relationship.<br>O A linear model is suitable because the scatterplot<br>of weeks against log(stock price) shows a strong<br>linear relationship.<br>log(Stock Price) vs. Weeks<br>O An exponential model is suitable because the<br>scatterplot of log(weeks) against log(stock price)<br>shows a curved relationship.<br>2.28<br>2.26<br>2.24<br>222<br>2.2<br>2.18<br>2.16<br>2.14<br>212<br>O An exponential model is suitable because the<br>scatterplot of weeks against log(stock price) shows<br>a strong linear relationship.<br>2.1<br>2.08<br>206<br>log(Stock Price)<br>

Extracted text: A popular social media platform has begun offering stock shares to the public. In the past 2 years, the price of the stock has generally increased. An investment specialist gathers data on the stock price over the past 2 years and proppses two models for estimating the growth of the steck, as shown in the scatterplots. Based on the scatterplots, which type of model is most suitable for estimating the stock price? O A power model is suitable because the scatterplot of log(weeks) against log(stock price) shows a curved relationship. O A linear model is suitable because the scatterplot of weeks against log(stock price) shows a strong linear relationship. log(Stock Price) vs. Weeks O An exponential model is suitable because the scatterplot of log(weeks) against log(stock price) shows a curved relationship. 2.28 2.26 2.24 222 2.2 2.18 2.16 2.14 212 O An exponential model is suitable because the scatterplot of weeks against log(stock price) shows a strong linear relationship. 2.1 2.08 206 log(Stock Price)
log(Stock Price) vs. log(Weeks)<br>2.28<br>2.26<br>2.24<br>2.22<br>22<br>2.18<br>2.16<br>2.14<br>2.12<br>21<br>2.08<br>2.06<br>2.04<br>0.5<br>1.<br>1.5<br>12,<br>log(Weeks)<br>log(Stock Price)<br>

Extracted text: log(Stock Price) vs. log(Weeks) 2.28 2.26 2.24 2.22 22 2.18 2.16 2.14 2.12 21 2.08 2.06 2.04 0.5 1. 1.5 12, log(Weeks) log(Stock Price)

Jun 07, 2022
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