A Phoenix Wealth Management/Harris Interactive survey of 1500 individuals with net worth of $1 million or more provided a variety of statistics on wealthy people (BusinessWeek, September 22,...

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A Phoenix Wealth Management/Harris Interactive survey of 1500 individuals with net worth of $1 million or more provided a variety of statistics on wealthy people (BusinessWeek, September 22, 2003). The previous three-year period had been bad for the stock market, which motivated some of the questions asked. a. The survey reported that 53% of the respondents lost 25% or more of their portfolio value over the past three years. Develop a 95% confidence interval for the proportion of wealthy people who lost 25% or more of their portfolio value over the past three years. b. The survey reported that 31% of the respondents feel they have to save more for retirement to make up for what they lost. Develop a 95% confidence interval for the population proportion. c. Five percent of the respondents gave $25,000 or more to charity over the previous year. Develop a 95% confidence interval for the proportion who gave $25,000 or more to charity. d. Compare the margin of error for the interval estimates in parts (a), (b), and (c). How is the margin of error related to ? When the same sample is being used to estimate a variety of proportions, which of the proportions should be used to choose the planning value p*? Why do you think p*  .50 is often used in these cases?

Answered Same DayDec 26, 2021

Answer To: A Phoenix Wealth Management/Harris Interactive survey of 1500 individuals with net worth of $1...

David answered on Dec 26 2021
131 Votes
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A 95% Confidence Interval for p1
p̂1 = 0.53,n = 1500
S
ignificance level = α = 1− confidence = 1 − 0.95 = 0.05
Critical z-value = zα/2 = z0.05/2 = z0.025 = 1.96 (From z table)
Standard error of p̂1 : SE =

p̂1 × (1 − p̂1)
n
=

0.53 × 0.47
1500 ≈ 0.012887
E = zα/2 ×

p̂1 × (1 − p̂1)
n
= 1.96 × 0.012887 ≈ 0.025258
Margin of Error, E = 0.0253
95% Confidence Interval is given by 0.53 ± 0.025258 :
Lower limit = p̂1 − E = 0.53 − 0.025258 ≈ 0.504742
Upper limit = p̂1 + E = 0.53 + 0.025258 ≈ 0.555258
95% CI for p1 : 0.505 < p1 < 0.555
Note that exact using technology answer is:
0.53 ± invNorm(0.05/2) × sqrt((0.53 ∗ (0.47))/1500)
(0.5047425603, 0.5552574397)
B 95% Confidence Interval for p1
p̂1 = 0.31,n = 1500
Significance level = α = 1− confidence = 1 − 0.95 =...
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