A horizontal curve with radius equal to 220 m. and intersection angle of 126 ° is to be realigned by rotating the forward tangent through an angle of 22° counterclockwise along the P.T. If the...


A horizontal curve with radius equal to 220 m. and intersection angle of 126<br>° is to be realigned by rotating the forward tangent through an angle of 22°<br>counterclockwise along the P.T. If the azimuths of the back and forward<br>tangents are 220° and 346° respectively, stationing of old P.C. is<br>10+721.20.<br>1. Compute the central angle of the new curve.<br>2. Compute the radius of the new curve.<br>3. What is the stationing of the new P.C.<br>

Extracted text: A horizontal curve with radius equal to 220 m. and intersection angle of 126 ° is to be realigned by rotating the forward tangent through an angle of 22° counterclockwise along the P.T. If the azimuths of the back and forward tangents are 220° and 346° respectively, stationing of old P.C. is 10+721.20. 1. Compute the central angle of the new curve. 2. Compute the radius of the new curve. 3. What is the stationing of the new P.C.

Jun 11, 2022
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