A given set of vectors is said to form a basis if the set of vectors are both linearly independent and forms a spanning set for the given space. In this exercise, the learners areasked to determine...


BASIS of Vectors<br>My Solutions ><br>A given set of vectors is said to form a basis if the set of vectors are both linearly independent and forms a spanning set for the given space. In this exercise, the learners are<br>asked to determine whether the concatenated vectors are spanning set, linearly independent and form a basis.<br>Required:<br>1. Create a function with three output [ss, li,bas] which will determine whether the vectors are spanning set, linearly independent and forms a basis for R^n.<br>2. The name of the function is splibas.<br>3. The function accepts the concatenated vectors A and the program will solve the reduced row echelon form from which the interpretation will be done whether the vectors are<br>linearly independent, spanning set and forming a basis for R^n<br>Resets the solution code to the<br>starter code provided by the<br>instructor. Changes you have<br>made are discarded.<br>Function e<br>A Save<br>C Reset<br>I MATLAB Documentation<br>1 %This program accepts the concatenated column vectors A, where the size of the Matrix will initially be checked. It will be transformed into its<br>2 %reduced row echelon form from which the program shall interpret whether it forms a basis, is linearly independent or spanning set for R^n.<br>Code to call your function e<br>C Reset<br>1 A = [1 2 3;4 5 6;7 8 9]<br>2 [SS1, LI1, BAS1] = splibas (A)<br>

Extracted text: BASIS of Vectors My Solutions > A given set of vectors is said to form a basis if the set of vectors are both linearly independent and forms a spanning set for the given space. In this exercise, the learners are asked to determine whether the concatenated vectors are spanning set, linearly independent and form a basis. Required: 1. Create a function with three output [ss, li,bas] which will determine whether the vectors are spanning set, linearly independent and forms a basis for R^n. 2. The name of the function is splibas. 3. The function accepts the concatenated vectors A and the program will solve the reduced row echelon form from which the interpretation will be done whether the vectors are linearly independent, spanning set and forming a basis for R^n Resets the solution code to the starter code provided by the instructor. Changes you have made are discarded. Function e A Save C Reset I MATLAB Documentation 1 %This program accepts the concatenated column vectors A, where the size of the Matrix will initially be checked. It will be transformed into its 2 %reduced row echelon form from which the program shall interpret whether it forms a basis, is linearly independent or spanning set for R^n. Code to call your function e C Reset 1 A = [1 2 3;4 5 6;7 8 9] 2 [SS1, LI1, BAS1] = splibas (A)
Jun 05, 2022
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