A gambler simulates a new card game on a computer. Out of 500 trials he wins 200 times. So he calculates P(winning) = 200/500 = 0.40. Why is this only an estimate of the true value of P(winning)? A. There are more than 2 events B. The outcomes are not equally likely C. His estimate is not rounded to 3 decimal places D. If he were to do a different set of 500 trials, he might win 180 times and calculate a different value of P(winning)

A gambler simulates a new card game on a computer. Out of 500 trials he wins 200 times. So he calculates P(winning) = 200/500 = 0.40. Why is this only an estimate of the true value of P(winning)?...

A gambler simulates a new card game on a computer. Out of 500 trials he wins 200 times. So he calculates P(winning) = 200/500 = 0.40. Why is this only an estimate of the true value of P(winning)?

There are more than 2 events

The outcomes are not equally likely

His estimate is not rounded to 3 decimal places

If he were to do a different set of 500 trials, he might win 180 times and calculate a different value of P(winning)

Jun 07, 2022

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A gambler simulates a new card game on a computer. Out of 500 trials he wins 200 times. So he calculates P(winning) = 200/500 = 0.40. Why is this only an estimate of the true value of P(winning)?...

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A gambler simulates a new card game on a computer. Out of 500 trials he wins 200 times. So he calculates​ P(winning) =​ 200/500 = 0.40. Why is this only an estimate of the true value of​ P(winning)?...

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A gambler simulates a new card game on a computer. Out of 500 trials he wins 200 times. So he calculates P(winning) = 200/500 = 0.40. Why is this only an estimate of the true value of P(winning)?...