A fruit grower wants to test a new spray that a manufacturer claims will reduce the loss due to insect damage. To test the claim, the grower sprays 200 trees with the new spray and 200 other trees...


A fruit grower wants to test a new spray that a manufacturer claims will reduce the loss due to insect damage. To test the<br>claim, the grower sprays 200 trees with the new spray and 200 other trees with the standard spray. The following data<br>were recorded.<br>New Spray<br>Standard Spray<br>Mean Yield per Tree x (Ib)<br>240<br>229<br>Variance s?<br>990<br>806<br>(a) Do the data provide sufficient evidence to conclude that the mean yield per tree treated with the new spray, µ,,<br>exceeds that for trees treated with the standard spray, u,? Use a = 0.05.<br>State the null and alternative hypotheses.<br>O Ho: (H1 – H2) = 0 versus Ha: (H1 - H2) > 0<br>O Ho: (H1 – µ2) = 0 versus H: (H1 – H2) < 0<br>O Ho: (H1<br>- H2) # 0 versus H: (H, – H2) = 0<br>O Ho: (H1 – H2) = 0 versus H3: (H1 – H2) # 0<br>O Ho: (H1 - H2) < 0 versus H,: (H1 - H2) > 0<br>Find the test statistic and rejection region. (Round your answers to two decimal places. If the test is one-tailed,<br>enter NONE for the unused region.)<br>test statistic<br>Z =<br>rejection region<br>z><br>z <<br>State your conclusion.<br>O Ho is not rejected. There is insufficient evidence to conclude that the mean yield per tree treated with the<br>new spray exceeds that for trees treated with the standard spray.<br>H, is rejected. There is insufficient evidence to conclude that the mean yield per tree treated with the new<br>spray exceeds that for trees treated with the standard spray.<br>H, is rejected. There is sufficient evidence to conclude that the mean yield per tree treated with the new<br>spray exceeds that for trees treated with the standard spray.<br>Ho is not rejected. There is sufficient evidence to conclude that the mean yield per tree treated with the<br>new spray exceeds that for trees treated with the standard spray.<br>(b) Construct a 95% confidence interval for the difference (u, - H2) between the mean yields for the two sprays<br>(in pounds). (Round your answers to two decimal places.)<br>Ib to<br>Ib<br>

Extracted text: A fruit grower wants to test a new spray that a manufacturer claims will reduce the loss due to insect damage. To test the claim, the grower sprays 200 trees with the new spray and 200 other trees with the standard spray. The following data were recorded. New Spray Standard Spray Mean Yield per Tree x (Ib) 240 229 Variance s? 990 806 (a) Do the data provide sufficient evidence to conclude that the mean yield per tree treated with the new spray, µ,, exceeds that for trees treated with the standard spray, u,? Use a = 0.05. State the null and alternative hypotheses. O Ho: (H1 – H2) = 0 versus Ha: (H1 - H2) > 0 O Ho: (H1 – µ2) = 0 versus H: (H1 – H2) < 0="" o="" ho:="" (h1="" -="" h2)="" #="" 0="" versus="" h:="" (h,="" –="" h2)="0" o="" ho:="" (h1="" –="" h2)="0" versus="" h3:="" (h1="" –="" h2)="" #="" 0="" o="" ho:="" (h1="" -="" h2)="">< 0="" versus="" h,:="" (h1="" -="" h2)=""> 0 Find the test statistic and rejection region. (Round your answers to two decimal places. If the test is one-tailed, enter NONE for the unused region.) test statistic Z = rejection region z> z < state your conclusion. o ho is not rejected. there is insufficient evidence to conclude that the mean yield per tree treated with the new spray exceeds that for trees treated with the standard spray. h, is rejected. there is insufficient evidence to conclude that the mean yield per tree treated with the new spray exceeds that for trees treated with the standard spray. h, is rejected. there is sufficient evidence to conclude that the mean yield per tree treated with the new spray exceeds that for trees treated with the standard spray. ho is not rejected. there is sufficient evidence to conclude that the mean yield per tree treated with the new spray exceeds that for trees treated with the standard spray. (b) construct a 95% confidence interval for the difference (u, - h2) between the mean yields for the two sprays (in pounds). (round your answers to two decimal places.) ib to ib state="" your="" conclusion.="" o="" ho="" is="" not="" rejected.="" there="" is="" insufficient="" evidence="" to="" conclude="" that="" the="" mean="" yield="" per="" tree="" treated="" with="" the="" new="" spray="" exceeds="" that="" for="" trees="" treated="" with="" the="" standard="" spray.="" h,="" is="" rejected.="" there="" is="" insufficient="" evidence="" to="" conclude="" that="" the="" mean="" yield="" per="" tree="" treated="" with="" the="" new="" spray="" exceeds="" that="" for="" trees="" treated="" with="" the="" standard="" spray.="" h,="" is="" rejected.="" there="" is="" sufficient="" evidence="" to="" conclude="" that="" the="" mean="" yield="" per="" tree="" treated="" with="" the="" new="" spray="" exceeds="" that="" for="" trees="" treated="" with="" the="" standard="" spray.="" ho="" is="" not="" rejected.="" there="" is="" sufficient="" evidence="" to="" conclude="" that="" the="" mean="" yield="" per="" tree="" treated="" with="" the="" new="" spray="" exceeds="" that="" for="" trees="" treated="" with="" the="" standard="" spray.="" (b)="" construct="" a="" 95%="" confidence="" interval="" for="" the="" difference="" (u,="" -="" h2)="" between="" the="" mean="" yields="" for="" the="" two="" sprays="" (in="" pounds).="" (round="" your="" answers="" to="" two="" decimal="" places.)="" ib="" to="">
Jun 09, 2022
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