a. For lactic acid (2-hydroxypropanoic acid), pKa = 3.86. Draw lactic acid as it would appear at pH 7. b. For diethylammonium ion, pKa = 11.1. Draw diethylammonium ion as it would appear at pH 7. a....

a. For lactic acid (2-hydroxypropanoic acid), pKa = 3.86. Draw lactic acid as it would appear at pH 7. b. For diethylammonium ion, pKa = 11.1. Draw diethylammonium ion as it would appear at pH 7. a. For 4-ethylphenol, Ka = 1 * 10-10. Draw this compound as it would appear at pH 7. b. For triethylammonium ion, Ka = 1 * 10-11. Draw this compound as it would appear at pH 7.