(a) Explain reasons to divide the physical memory of 8086 into segments. Suppose that DS= XX00H, BX= 0210H and DI = 0010H. Determine the memory address accessed by each of the following instructions:...

(a) Explain reasons to divide the physical memory of 8086 into segments.<br>Suppose that DS= XX00H, BX= 0210H and DI = 0010H. Determine the<br>memory address accessed by each of the following instructions:<br>[5]<br>i. MOV AL, [1234H]<br>ii. MOV AX, [BX]<br>iii. MOV [BX+DI+200H], AL<br>(hints: Replace XX with the last 2 digits of your student ID)<br>

Extracted text: (a) Explain reasons to divide the physical memory of 8086 into segments. Suppose that DS= XX00H, BX= 0210H and DI = 0010H. Determine the memory address accessed by each of the following instructions: [5] i. MOV AL, [1234H] ii. MOV AX, [BX] iii. MOV [BX+DI+200H], AL (hints: Replace XX with the last 2 digits of your student ID)

Jun 09, 2022

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(a) Explain reasons to divide the physical memory of 8086 into segments. Suppose that DS= XX00H, BX= 0210H and DI = 0010H. Determine the memory address accessed by each of the following instructions:...

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