A distribution of values is normal with a mean of 213.9 and a standard deviation of 48.6. Use exact z-scores or z-scores rounded to 2 decimal places. Find the probability that a randomly selected...

Extracted text: A distribution of values is normal with a mean of 213.9 and a standard deviation of 48.6. Use exact z-scores or z-scores rounded to 2 decimal places. Find the probability that a randomly selected value is greater than 170.2. P(X > 170.2) = Enter your answer as a number accurate to 4 decimal places. Submit Question