. A discrete random variable taking values 0, 1, . . . is said to have a geometric distribution with parameter p if P(N = k) = (1 − p) pk−1, k = 1, 2, . . . . a. Suppose that X is exponential with...



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A discrete random variable taking values 0, 1, . . . is said to have


a geometric distribution with parameter p if


P(N = k) = (1 − p) pk−1, k = 1, 2, . . . .


a. Suppose that X is exponential with parameter λ, and define a new random


variable N by


N = k if k − 1<>≤ k.


Show that N is geometric, and identify p.


b. Show that the mean EN of the geometric is 1/(1 − p), and calculate the


variance. [Hint: One way to do this is to complete the steps below:


For the variance, differentiate twice.]


c. The geometric arises as the distribution of the number of tosses up to and


including the first tail in a sequence of independent coin tosses in which


the probability of a head is p. Use this to calculate the distribution of N.


Can you derive EN using the waiting time analogy?








May 22, 2022
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