A current mirror consisting of two matched BJTs can be imbalanced on purpose by inserting a resistance R in series with the emitter of one of its two BJTs. In we have inserted R in series with the...

A current mirror consisting of two matched BJTs can be imbalanced on purpose by inserting a resistance R in series with the emitter of one of its two BJTs. In we have inserted R in series with the emitter of Q2 to lower IC2 relative to IC1. Let us now investigate the opposite case, namely, the insertion of R in series with the emitter of Q1 to increase IC2 relative to IC1. Redraw the circuit of but with Q2’s emitter at ground and with R in series between Q1’s emitter and ground. (a) If VCC 5 5 V and the BJTs are matched and have Is 5 2 fA, VA 5 `, and negligible base currents, specify suitable values for R1 and R to ensure IC1 5 0.5 mA and IC2 5 2 mA. (b) If VCC is increased until IC1 5 1 mA, what is the new value of IC2? Hint: use the rules of thumb.