A continuous-time signal has the bilateral Laplace transform 1 F,(s): s-4 Re(s)

Signal and System Analysis

A continuous-time signal has the bilateral Laplace transform<br>1<br>F,(s):<br>s-4<br>Re(s) < 3. Then f(t) is<br>3 <<br>s-3<br>s+3'<br>-3t<br>А. е<br>u(t) – 2e-3t<br>u(-t) + e*t u(-t)<br>B. 2e-3t u(t) + e3t u(t) – et u(-t)<br>u(t) + e³t u(-t) + e** u(-t)<br>u(t) – et u(-t) – et u(-t)<br>u(t) + 2ešt u(-t) + e* u(-t)<br>on<br>-3t<br>С. е<br>D. 2e<br>-3t<br>-3t<br>E. e<br>O I.A.<br>O II. B<br>O II. C<br>O IV. D<br>OV.E<br>

Extracted text: A continuous-time signal has the bilateral Laplace transform 1 F,(s): s-4 Re(s) < 3.="" then="" f(t)="" is="" 3="">< s-3="" s+3'="" -3t="" а.="" е="" u(t)="" –="" 2e-3t="" u(-t)="" +="" e*t="" u(-t)="" b.="" 2e-3t="" u(t)="" +="" e3t="" u(t)="" –="" et="" u(-t)="" u(t)="" +="" e³t="" u(-t)="" +="" e**="" u(-t)="" u(t)="" –="" et="" u(-t)="" –="" et="" u(-t)="" u(t)="" +="" 2ešt="" u(-t)="" +="" e*="" u(-t)="" on="" -3t="" с.="" е="" d.="" 2e="" -3t="" -3t="" e.="" e="" o="" i.a.="" o="" ii.="" b="" o="" ii.="" c="" o="" iv.="" d="">

Jun 11, 2022

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A continuous-time signal has the bilateral Laplace transform 1 F,(s): s-4 Re(s)

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