A computer system has the segmented paging for virtual memory. The memory is byte addressable. Both virtual and physical address spaces contain 216 bytes each. The virtual address space is divided...


A computer system has the segmented paging for virtual memory. The memory is byte addressable. Both virtual and physical address spaces contain<br>216<br>bytes each. The virtual address space is divided into 8 non-overlapping equal size segments. The memory management unit has a hardware<br>segment table, each entry of which contains the physical address of the page table for the segment. Page tables are stored in the main memory and consists of<br>2 byte page table entries What is the minimum page size in bytes so that the page table for a segment requires at most one page to store it and also give the<br>division of virtual address ?<br>

Extracted text: A computer system has the segmented paging for virtual memory. The memory is byte addressable. Both virtual and physical address spaces contain 216 bytes each. The virtual address space is divided into 8 non-overlapping equal size segments. The memory management unit has a hardware segment table, each entry of which contains the physical address of the page table for the segment. Page tables are stored in the main memory and consists of 2 byte page table entries What is the minimum page size in bytes so that the page table for a segment requires at most one page to store it and also give the division of virtual address ?

Jun 04, 2022
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