A circular tank open to the atmosphere, with a cross-sectional area of 6 ft2 , is filled with water to a depth of h = h1 = 9 ft above the centerline of the 0.95-in-diameter plugged opening near the...


A circular tank open to the atmosphere, with a cross-sectional area of 6 ft2 , is filled with water to a depth of h = h1 = 9 ft above the centerline of the 0.95-in-diameter plugged opening near the bottom of the tank, as illustrated in Figure ECP 3.61. When the opening is unplugged it will be open to the atmosphere, and a jet of water will flow at a variable velocity, v(h) = 2gh  (derived from applying the Bernoulli equation in Chapter 4). (a) Determine the variable volume flowrate of flow through the jet. (b) Determine the time it takes for the water in the tank to reach a depth h = h2 = 6 ft above the centerline of the jet. (c) Determine the rate of change of the depth of water in the tank, vtan k(h) = (dh/dt) when the water in the tank is at a depth h = h2 = 6 ft above the centerline of the jet.

Nov 19, 2021
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