A certain brand of automobile tire has a mean life span of 37000 miles and a standard deviation of2150 miles.
Extracted text: A certain brand of automobile tire has a mean life span of 37,000 miles and a standard deviation of 2,150 miles. (Assume the life spans of the tires have a bell-shaped distribution.) (a) The life spans of three randomly selected tires are 35,000 miles, 38,000 miles, and 32,000 miles. Find the z-score that corresponds to each life span. For the life span of 35,000 miles, z-score is -0.93. (Round to the nearest hundredth as needed.) For the life span of 38,000 miles, z-score is 0.47. (Round to the nearest hundredth as needed.) For the life span of 32,000 miles, z-score is - 2.33 (Round to the nearest hundredth as needed.) According to the z-scores, would the life spans of any of these tires be considered unusual? Yes No (b) The life spans of three randomly selected tires are 32,700 miles, 41,300 miles, and 37,000 miles. Using the empirical rule, find the percentile that corresponds to each life span. The life span 32,700 miles corresponds to the 2.5 th percentile. The life span 41,300 miles corresponds to the 97.5 th percentile. The life span 37,000 miles corresponds to the 50 th percentile.