Extracted text: A base line was measured in catenary in four lengths giving 30.126, 29.973, 30.066, and 22.536 meters. The differences of level were respectively 0.45, 0.60, 0.30, and 0.45 meters. The temperature during the observation was 10°C and the tension applied is 15 kg. The tape was standardized as 30 meters at 20°C, on the flat with a tension of 5 kg. The coefficient of expansion was 0.0000116 per °C, the weight of the tape is 1 kg, the cross-sectional area is 3 mm?, E=210x103 N/mm?(210 kN/mm?), gravitational acceleration is g=9.80665 m/s?. The total correction due to pull is meters (Round your answer to six decimal places.) The total correction due to temperature is meters (Round your answer to six decimal places.) The total correction due to sag is meters. (Round your answer to six decimal places.) The total correction due to slope is (Round your answer to six decimal places.) The total combined correction is meters. (Round your answer to six decimal places if necessary.) The correct length of the line is meters. (Round your answer to four decimal places if necessary.) The normal tension is kilograms. (Round your answer to six decimal places.)