A 600-mm-radius sewer pipe is laid on a slope of 0.001 and has a coefficient n = 0.012, was found to be 7/8 full. Determine the through the pipe. roughness discharge Problem 8-5 (CE Board May 1993)...

Explain every step of the solution thank you.A 600-mm-radius sewer pipe is laid on a slope of 0.001 and has a<br>coefficient n = 0.012, was found to be 7/8 full. Determine the<br>through the pipe.<br>roughness<br>discharge<br>Problem 8-5 (CE Board May 1993)<br>Solution<br>A<br>r 0.6 m<br>r= 0.6 m<br>4.<br>360-0<br>0.6 m<br>Q = A - R2/351/2<br>A=D 좋Atotal<br>T (0.6)2<br>%3D<br>A = 0.9896 m2<br>A1 = Atwtal - A = a 1²<br>A1 = Asector Atriangle<br>%3D<br>

Extracted text: A 600-mm-radius sewer pipe is laid on a slope of 0.001 and has a coefficient n = 0.012, was found to be 7/8 full. Determine the through the pipe. roughness discharge Problem 8-5 (CE Board May 1993) Solution A r 0.6 m r= 0.6 m 4. 360-0 0.6 m Q = A - R2/351/2 A=D 좋Atotal T (0.6)2 %3D A = 0.9896 m2 A1 = Atwtal - A = a 1² A1 = Asector Atriangle %3D
FLUID MECHANICS<br>&HYDRAULICS<br>CHAPTER EIGHT<br>Open Cnannel<br>a2= 0,-r² sin 0<br>0,-sin 0 0.785<br>Solve 0 by trial and error:<br>0 = 101.185°<br>%3D<br>101.185°(T/180°) – sin (101.185°) = 0.785 (OK)<br>Then;<br>T((0.6)(360° - 101.185°)<br>P =<br>180°<br>P 2.71 m<br>R = A/P = 0.9896/2.71<br>R 0.365 m.<br>Q= (0.9896) dz (0.365)/(0.001)/2<br>Q = 1.332 m/s<br>Problem 8- 6<br>

Extracted text: FLUID MECHANICS &HYDRAULICS CHAPTER EIGHT Open Cnannel a2= 0,-r² sin 0 0,-sin 0 0.785 Solve 0 by trial and error: 0 = 101.185° %3D 101.185°(T/180°) – sin (101.185°) = 0.785 (OK) Then; T((0.6)(360° - 101.185°) P = 180° P 2.71 m R = A/P = 0.9896/2.71 R 0.365 m. Q= (0.9896) dz (0.365)/(0.001)/2 Q = 1.332 m/s Problem 8- 6

Jun 11, 2022
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