A =1B =1 C=5 We have a string with length that is attached at both ends, both at x = 0 and x = 1. The differential equation and boundary conditions that describe the position u as a function of x and...


send handwritten solution for part a


A =1B =1 C=5<br>We have a string with length that is attached at both ends, both at x = 0 and x = 1. The<br>differential equation and boundary conditions that describe the position u as a function of x and<br>are given by<br>Uu(x,t) = c²u» (x,t), 0<x < l, 0<t<∞<br>0<t<∞o,<br>u(0,t) = u(l,t) = 0, 0<t< ∞,<br>where the constant c is the wave speed of the string<br>At time t = 0 we pull the middle of the string to a height h from the equilibrium position so that<br>the position of the string is given by<br>0< x <<br>u(x,0) =<br>u;(x,0) = 0<br>All points on the string have a starting speed of zero at time t= 0, je<br>for 0<x <1.<br>(a) Write down the general solutions for position and speed of this string. Make<br>simplifications as a result of the starting conditions<br>(b) Calculate the coefficients of the general solutions so that you arrive at a solution for<br>position and speed of the string as a function of I and h. To arrive at the solution, the<br>following can be used<br>(c) Explain, using the solution to the wave equation, why maximum speed is reached in the<br>middle of the string<br>(d) Find the wave velocity of the string given that the oscillation time T for an entire period is<br>B seconds and the length I is your candidate number in centimeters (ABCcm). The value of<br>B = 1. T= 5s and I= 115cm.<br>(e) At what times does the string have the greatest speed?<br>

Extracted text: A =1B =1 C=5 We have a string with length that is attached at both ends, both at x = 0 and x = 1. The differential equation and boundary conditions that describe the position u as a function of x and are given by Uu(x,t) = c²u» (x,t), 0< l,=""><><∞><><∞o, u(0,t)="u(l,t)" =="" 0,=""><>< ∞,="" where="" the="" constant="" c="" is="" the="" wave="" speed="" of="" the="" string="" at="" time="" t="0" we="" pull="" the="" middle="" of="" the="" string="" to="" a="" height="" h="" from="" the="" equilibrium="" position="" so="" that="" the="" position="" of="" the="" string="" is="" given="" by="">< x="">< u(x,0)="u;(x,0)" =="" 0="" all="" points="" on="" the="" string="" have="" a="" starting="" speed="" of="" zero="" at="" time="" t="0," je="" for=""><1. (a)="" write="" down="" the="" general="" solutions="" for="" position="" and="" speed="" of="" this="" string.="" make="" simplifications="" as="" a="" result="" of="" the="" starting="" conditions="" (b)="" calculate="" the="" coefficients="" of="" the="" general="" solutions="" so="" that="" you="" arrive="" at="" a="" solution="" for="" position="" and="" speed="" of="" the="" string="" as="" a="" function="" of="" i="" and="" h.="" to="" arrive="" at="" the="" solution,="" the="" following="" can="" be="" used="" (c)="" explain,="" using="" the="" solution="" to="" the="" wave="" equation,="" why="" maximum="" speed="" is="" reached="" in="" the="" middle="" of="" the="" string="" (d)="" find="" the="" wave="" velocity="" of="" the="" string="" given="" that="" the="" oscillation="" time="" t="" for="" an="" entire="" period="" is="" b="" seconds="" and="" the="" length="" i="" is="" your="" candidate="" number="" in="" centimeters="" (abccm).="" the="" value="" of="" b="1." t="5s" and="" i="115cm." (e)="" at="" what="" times="" does="" the="" string="" have="" the="" greatest="">

Jun 05, 2022
SOLUTION.PDF

Get Answer To This Question

Related Questions & Answers

More Questions »

Submit New Assignment

Copy and Paste Your Assignment Here