A 1.2040 g sample containing sodium carbonate and inert material was dissolved in water and titrated to methyl orange end point, requiring 32.50 mL of 0.1020 M HCI. Calculate the %N22CO3 in the...

A 1.2040 g sample containing sodium carbonate and inert material was dissolved in water and titrated to methyl orange end<br>point, requiring 32.50 mL of 0.1020 M HCI. Calculate the %N22CO3 in the sample.<br>A) 93.36%<br>B) 23.41%<br>C) 14.59%<br>D) 12.75%<br>

Extracted text: A 1.2040 g sample containing sodium carbonate and inert material was dissolved in water and titrated to methyl orange end point, requiring 32.50 mL of 0.1020 M HCI. Calculate the %N22CO3 in the sample. A) 93.36% B) 23.41% C) 14.59% D) 12.75%

Jun 07, 2022

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A 1.2040 g sample containing sodium carbonate and inert material was dissolved in water and titrated to methyl orange end point, requiring 32.50 mL of 0.1020 M HCI. Calculate the %N22CO3 in the...

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