could you make it clear?Extracted text: 9.38 Consider Example 9.6 with the null hypothesis Họ:P = Po = 0.50 and the alternative hypothesis Ho:P # 0.50 The decision rule is Pz - 0.50 V0.50(1 – 0.50)/600 Px - 0.50 V0.50(1 – 0.50)/600 1.96 with a sample size of n = 600. What is the probability of Type II error if the actual population proportion is each of the following? a. P = 0.52 b. P = 0.58 c. P = 0.53 d. P = 0.48 %3D e. P = 0.43

9.38 Consider Example 9.6 with the null hypothesis Họ:P = Po = 0.50 and the alternative hypothesis Ho:P # 0.50 The decision rule is Pz - 0.50 V0.50(1 – 0.50)/600 Px - 0.50 V0.50(1 – 0.50)/600 1.96...

could you make it clear?

9.38 Consider Example 9.6 with the null hypothesis<br>Họ:P = Po = 0.50<br>and the alternative hypothesis<br>Ho:P # 0.50<br>The decision rule is<br>Pz - 0.50<br>V0.50(1 – 0.50)/600<br>Px - 0.50<br>V0.50(1 – 0.50)/600<br>< -1.96 or<br>> 1.96<br>with a sample size of n = 600. What is the probability<br>of Type II error if the actual population proportion is<br>each of the following?<br>a. P = 0.52<br>b. P = 0.58<br>c. P = 0.53<br>d. P = 0.48<br>%3D<br>e. P = 0.43<br>

Extracted text: 9.38 Consider Example 9.6 with the null hypothesis Họ:P = Po = 0.50 and the alternative hypothesis Ho:P # 0.50 The decision rule is Pz - 0.50 V0.50(1 – 0.50)/600 Px - 0.50 V0.50(1 – 0.50)/600 < -1.96="" or=""> 1.96 with a sample size of n = 600. What is the probability of Type II error if the actual population proportion is each of the following? a. P = 0.52 b. P = 0.58 c. P = 0.53 d. P = 0.48 %3D e. P = 0.43

Jun 10, 2022

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9.38 Consider Example 9.6 with the null hypothesis Họ:P = Po = 0.50 and the alternative hypothesis Ho:P # 0.50 The decision rule is Pz - 0.50 V0.50(1 – 0.50)/600 Px - 0.50 V0.50(1 – 0.50)/600 1.96...

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