8.38 The equation of the catenary shown is y = 100 cosh(x/100) where x and y are measured in feet (the catenary is the shape of a cable suspended between two points). Locate the y-coordinate of the...


8.38 The equation of the catenary shown is y = 100 cosh(x/100) where x and y<br>are measured in feet (the catenary is the shape of a cable suspended between<br>two points). Locate the y-coordinate of the centroid of the catenary by numerical<br>integration using Ax = 25 ft.<br>25 ft<br>- 100 ft-<br>- 100 ft-<br>Fig. P8.38<br>Answer: 119.7ft<br>154.3 ft<br>U00L<br>154.3 ft<br>

Extracted text: 8.38 The equation of the catenary shown is y = 100 cosh(x/100) where x and y are measured in feet (the catenary is the shape of a cable suspended between two points). Locate the y-coordinate of the centroid of the catenary by numerical integration using Ax = 25 ft. 25 ft - 100 ft- - 100 ft- Fig. P8.38 Answer: 119.7ft 154.3 ft U00L 154.3 ft

Jun 10, 2022
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