Extracted text: 8. Solve the following LP algebraically. Max Z = 150X+ 160Y f. Max Z= 650X +910Y а. subject to: subject to: 15 -Y<105 2="" x+="">105>< 50="" 4x+="" x=""> 20 31 49 -Y< 90="" 10="" y=""> 15 5 Χ Υ>0 91 41 Y<100 10="" b.="" min="" z="2x," +="" 3x2="" +="" x3="" 10="" subject="" to:="" x,="" y="">0 x, +x, > 10 g. Max Z= 5x, + 2x, + 8x, x, + x, > 15 subject to: x, + x, + x, > 20 X,- 2x, + < 420="" x1,="" x2,="" x3="" 20="" 2x,="" +="" 3x,="" –="">< 610="" c.="" min="" z="50x," +="" 40x2="" 6x,="" -="" x,="" +="" 3x,="">< 125="" subject="" to:="" x1,="" x2,="" x3="" 2="" 0="" 2x,="" +="" x,="" 2="" 12="" h.="" min="" z="30x," +="" 40x,="" 2x,="" +="" 9x,=""> 36 subject to: 2x, + 3x, 2 24 X; + 3x, > 6 X1, X2 20 x, +x, > 4 x, + 2x, < 8="" x1,="" x2="" 2="" 0="" d.="" min="" z="10x," +="" 30x,="" +="" 40x,="" +="" 20x4="" subject="" to:="" x2="" +="" x,=""> 20 Min Z= 20x; + 20x, i. x, + x, + x3 +x4 > 50 subject to: X1, X2, X3, X4NO 10x, + 30x, < 120="" e.="" max="" z="30x," +="" 40x2="" 30x,="" +="" 30x,=""> 130 subject to: 10x, – 10x, = 30 x, + 2x, < 12="" x1,="" x,="" 2="" 0="" -x,="" +="" 2x,="">< 8="" 2x,="" +="" x,="" 2="" 16="" x1,="" x2="">
100>