8.(ii) We will use a = 0.05.(iii) We will assume that the fill amount is normally distributed. We will reject Ho if Zstat > XXXXXXXXXXIn our caseХn —8Zstat == 5.0 > 1.645.ol nSo, the evidence...

8. (ii) We will use a = 0.05. (iii) We will assume that the fill amount is normally distributed. We will reject Ho if Zstat > 1.645. In our case Хn —8 Zstat = = 5.0 > 1.645. ol n So, the evidence suggests that Họ should be rejected. (b) (i) Ho : µ < 8,="" versus="" h1="" :µ=""> 8. (ii) We will use a = 0.01. (iii) We will assume that the fill amount is normally distributed. We will reject Ho if Zstat > 1.645. In our case Xn – 8 Zstat = = 5.0 > 1.645. ol yn So, the evidence suggests that Họ should be rejected. (c) (i) Ho : µ < 8,="" versus="" h1="" :4=""> 8. (ii) We will use a = 0.001. (iii) We will assume that the fill amount is normally distributed. We will reject Ho if Zstat > 1.96. In our case Xn- 8 Zstat = = 5.0 < 1.96.="" ol="" n="" so,="" the="" evidence="" suggests="" that="" họ="" should="" not="" be="" rejected.="" (d)="" (i)="" ho="" :="" µ="">< 8,="" versus="" h1="" :="" µ=""> 8. (ii) We will use a = 0.05. (iii) We will assume that the fill amount is normally distributed. We will reject Ho if Zstat > 0.05. In our case Xn - 8 = 5.0 > 0.05. Zstat = ol yn So, the evidence suggests that Họ should be rejected. (e) None of the above. The correct answer is (а) (b) (c) (d) (e) N/A (Select One) "/>
Extracted text: An automatic coffee filling process is in control when the average amount of instant coffee that is poured into a jar is 8 oz and the standard deviation is 0.2 oz. A simple random sample of 100 jars is selected and the sample average is found to be x = 8.1 oz. Assuming the standard deviation of the process is still 0.2 oz, is the process out of control (pouring too much coffee into the jars) after specifying the following: (i) State your null and alternative hypotheses. (ii) State your level of significance. (iii) Specify any assumptions you made while reaching at your conclusion. The following`answers" have been proposed. (a) (i) Ho : µ < 8,="" versus="" h1="" :µ=""> 8. (ii) We will use a = 0.05. (iii) We will assume that the fill amount is normally distributed. We will reject Ho if Zstat > 1.645. In our case Хn —8 Zstat = = 5.0 > 1.645. ol n So, the evidence suggests that Họ should be rejected. (b) (i) Ho : µ < 8,="" versus="" h1="" :µ=""> 8. (ii) We will use a = 0.01. (iii) We will assume that the fill amount is normally distributed. We will reject Ho if Zstat > 1.645. In our case Xn – 8 Zstat = = 5.0 > 1.645. ol yn So, the evidence suggests that Họ should be rejected. (c) (i) Ho : µ < 8,="" versus="" h1="" :4=""> 8. (ii) We will use a = 0.001. (iii) We will assume that the fill amount is normally distributed. We will reject Ho if Zstat > 1.96. In our case Xn- 8 Zstat = = 5.0 < 1.96.="" ol="" n="" so,="" the="" evidence="" suggests="" that="" họ="" should="" not="" be="" rejected.="" (d)="" (i)="" ho="" :="" µ="">< 8,="" versus="" h1="" :="" µ=""> 8. (ii) We will use a = 0.05. (iii) We will assume that the fill amount is normally distributed. We will reject Ho if Zstat > 0.05. In our case Xn - 8 = 5.0 > 0.05. Zstat = ol yn So, the evidence suggests that Họ should be rejected. (e) None of the above. The correct answer is (а) (b) (c) (d) (e) N/A (Select One)