8 - A homogeneously charged thin rod is bent so that it becomes part of a circle of radius R. If the angle seeing the arc is A and the linear charge density is P, what is the electric field at the...


8 -<br>A homogeneously charged thin rod is bent so that it becomes part of a circle of radius R. If the angle seeing the arc is A and the linear charge density is P, what is the electric field at the center of the circle?<br>a) E=(2kP/R)sin(A)<br>O B) E=(2kP/R)sin(2A)<br>O C) E=(2KPR)sin(A/2)<br>O D) E=(4kP/R)sin(A/2)<br>O TO) E=(2kP/R)sin(A/2)<br>

Extracted text: 8 - A homogeneously charged thin rod is bent so that it becomes part of a circle of radius R. If the angle seeing the arc is A and the linear charge density is P, what is the electric field at the center of the circle? a) E=(2kP/R)sin(A) O B) E=(2kP/R)sin(2A) O C) E=(2KPR)sin(A/2) O D) E=(4kP/R)sin(A/2) O TO) E=(2kP/R)sin(A/2)

Jun 11, 2022
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