[8] 3. In a process of sintering(heating) two types of copper powder, the density function for Y1, the volume proportion of solid copper in a sample, was given by 6y1(1 – yı) 0

[8] 3. In a process of sintering(heating) two types of copper powder, the density function for Y1, the<br>volume proportion of solid copper in a sample, was given by<br>6y1(1 – yı) 0 < y1 <1<br>f1(y1) =<br>elsewhere<br>The density function for Y2, the proportion of type A crystals among the solid copper, was<br>given as<br>|3y3 0< y2 < 1<br>f2(y2) =<br>0.<br>elsewhere<br>The variable U = Y¡Y2 gives the proportion of the sample volume due to type A crystals. If<br>Y and Y, are independent, find the probability density function for U.<br>

Extracted text: [8] 3. In a process of sintering(heating) two types of copper powder, the density function for Y1, the volume proportion of solid copper in a sample, was given by 6y1(1 – yı) 0 < y1=""><1 f1(y1)="elsewhere" the="" density="" function="" for="" y2,="" the="" proportion="" of="" type="" a="" crystals="" among="" the="" solid="" copper,="" was="" given="" as="" |3y3="">< y2="">< 1="" f2(y2)="0." elsewhere="" the="" variable="" u="Y¡Y2" gives="" the="" proportion="" of="" the="" sample="" volume="" due="" to="" type="" a="" crystals.="" if="" y="" and="" y,="" are="" independent,="" find="" the="" probability="" density="" function="" for="">

Jun 09, 2022

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[8] 3. In a process of sintering(heating) two types of copper powder, the density function for Y1, the volume proportion of solid copper in a sample, was given by 6y1(1 – yı) 0

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