7:02 ..l .l ? 38 Activity 6- normal prob. Activity 6 Normal Probability Distribution 1. Draw and calculate the area under the standard normal curve to the left of these values: a. z= 1.6 b. z= 0.90 C....

Statistics

Extracted text: 7:02 ..l .l ? 38 Activity 6- normal prob. Activity 6 Normal Probability Distribution 1. Draw and calculate the area under the standard normal curve to the left of these values: a. z= 1.6 b. z= 0.90 C. Z= 1.83 2. Draw and find the probabilities for the following: a. between these values: z= -1.43 and 0.68 b. z>1.34 c. between 0.58 and 1.74 3. A variable x has a mean u = 10 and standard deviation o =2. Find the probabilities of these x-values: a. x<8.2 c.=""><><10.6 4.="" human="" heights="" are="" one="" of="" many="" variables="" that="" can="" be="" modelled="" by="" the="" normal="" distribution.="" assume="" the="" heights="" of="" men="" have="" a="" mean="" of="" 69="" inches="" with="" a="" standard="" deviation="" of="" 3.5="" inches.="" a.="" what="" proportion="" of="" all="" men="" will="" be="" taller="" than="" 6="" feet?="" (hint:="" convert="" the="" measurement="" to="" inches)="" b.="" what="" is="" the="" probability="" that="" selected="" man="" will="" be="" between="" 5'8"="" and="" 6'1'="" tall?="" 5.="" the="" discharge="" of="" suspended="" solids="" from="" a="" phosphate="" mine="" is="" normally="" distributed,="" with="" a="" mean="" daily="" discharge="" of="" 27="" milligrams="" per="" liter="" (mg/l)="" and="" a="" standard="" deviation="" of="" 14="" mg/l.="" what="" proportion="" of="" days="" will="" the="" daily="" discharge="" exceed="" 50="">


Extracted text: 4. Human heights are one of many variables that can be modelled by the normal distribution. Assume the heights of men have a mean of 69 inches with a standard deviation of 3.5 inches. a. What proportion of all men will be taller than 6 feet? (Hint: Convert the measurement to inches) b. What is the probability that selected man will be between 5'8" and 6'1' tall?