7. A researcher is asked to determine whether or not a productivity objective (in dollars) of better than $75,000 per employee is possible. A productivity test is done involving 20 employees. What...

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7. A researcher is asked to determine whether or not a productivity


objective (in dollars) of better than $75,000 per employee is


possible. A productivity test is done involving 20 employees. What


conclusion would you reach? The sales results are as follows:


a. 28,000 105,000 58,000 93,000 96,000


b. 67,000 82,500 75,000 81,000 59,000


c. 101,000 60,500 77,000 72,500 48,000


d. 99,000 78,000 71,000 80,500 78,000


8. Assume you have the following data:




H1:200,S30,



n





64, and


__



X





218. Conduct a two-tailed hypothesis test at


the 0.05 significance level.


9. If the data in question 8 had been generated with a sample of


25 (




n25), what statistical test would be appropriate?


10. The answers to a researcher’s question will be nominally scaled.


What statistical test is appropriate for comparing the sample data


with hypothesized population data?



Answered Same DayDec 20, 2021

Answer To: 7. A researcher is asked to determine whether or not a productivity objective (in dollars) of better...

David answered on Dec 20 2021
123 Votes
Answer 7:
Null Hypothesis (Ho): µ = 75000
Alternative Hypothesis (Ha): µ > 75000
Test Statistics

t = (X-bar - µ)/ (s/√n)
= (75500 – 75000)/ (18968.12/√20)
= 0.12
Degrees of freedom, df = n – 1 = 20 – 1 = 19
Using t-tables, the critical value is
t (0.05, 19) = ± 2.093
Since test statistics is within the critical value, we fail to reject the null hypothesis.
We can conclude that productivity objective (in dollars) of better than $75,000 per employee is not possible.
Answer 8:
Null Hypothesis (Ho): µ = 200
Alternative Hypothesis (Ha): µ ≠ 200
Test Statistics
Z = (X-bar - µ)/ (σ/√n)
= (218 – 200)/ (30/√64)
= 4.80
Using Z-tables, the critical value is
Z (0.05/2) = Z (0.025) = ± 1.96
Since test statistics is...
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