7 3.1OC. Ho: H=3.6Hai u>3.1Hai us3.1Hai u#3.6OF. Ho: H>3.6OD. Ho: H#3.1Ha:u =3.1O E. Ho:S3.6Ha:u> 3.6Hius3.6(b) Identify the standardized test statistic.(Round to two decimal places as...

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Extracted text: A nutritionist claims that the mean tuna consumption by a person is 3.6 pounds per year. A sample of 50 people shows that the mean tuna consumption by a person is 3.1 pounds per year. Assume the population standard deviation is 1.12 pounds. At a = 0.06, can you reject the claim? (a) Identify the null hypothesis and alternative hypothesis. ΟΑ H : μ53.1 O B. Ho:H>3.1 OC. Ho: H=3.6 Hai u>3.1 Hai us3.1 Hai u#3.6 OF. Ho: H>3.6 OD. Ho: H#3.1 Ha:u =3.1 O E. Ho:S3.6 Ha:u> 3.6 Hius3.6 (b) Identify the standardized test statistic. (Round to two decimal places as needed.) (c) Find the P-value. (Round to three decimal places as needed.) (d) Decide whether to reject or fail to reject the null hypothesis. O A. Fail to reject Ho. There is not sufficient evidence to reject the claim that mean O B. Fail to reject Ho. There is sufficient evidence to reject the claim that mean tuna consumption is equal to 3.6 pounds. tuna consumption is equal to 3.6 pounds. O D. Reject Ho. There is sufficient evidence to reject the claim that mean tuna consumption is equal to 3.6 pounds. O C. Reject Ho. There is not sufficient evidence to reject the claim that mean tuna consumption is equal to 3.6 pounds.