6) What is the actual volumetric flow rate in ft?/sec for the discharge of a tank through a 0.5 ft? orifice under a head of 8 ft water, if the coefficient of contraction for the orifice is 0.61 and...


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6) What is the actual volumetric flow rate in ft?/sec for the discharge of a tank through a 0.5 ft?<br>orifice under a head of 8 ft water, if the coefficient of contraction for the orifice is 0.61 and the<br>coefficient of velocity is 0.98?<br>

Extracted text: 6) What is the actual volumetric flow rate in ft?/sec for the discharge of a tank through a 0.5 ft? orifice under a head of 8 ft water, if the coefficient of contraction for the orifice is 0.61 and the coefficient of velocity is 0.98?
DEVELOPED HEAD:<br>Bernoulli Equation:<br>(P2, azV?<br>+<br>2gc<br>a,V?<br>+ 21°<br>2gc<br>Притр Wpитр<br>+ z2<br>P2<br>gc<br>The quantities in parenthesis are called TOTAL HEADS and are denoted by H.<br>Therefore: Wp<br>Нь-На<br>AH<br>POWER REQUIREMENT:<br>PB = m Wp = m AH<br>Pr<br>%3D<br>EDIFICA<br>where:<br>Pa, Po = pressure at the suction and discharge lines<br>V = velocity<br>H = total head<br>Ps = the power supplied to the pump<br>Z = height above the datum plane<br>P: = the power delivered to the fluid<br>

Extracted text: DEVELOPED HEAD: Bernoulli Equation: (P2, azV? + 2gc a,V? + 21° 2gc Притр Wpитр + z2 P2 gc The quantities in parenthesis are called TOTAL HEADS and are denoted by H. Therefore: Wp Нь-На AH POWER REQUIREMENT: PB = m Wp = m AH Pr %3D EDIFICA where: Pa, Po = pressure at the suction and discharge lines V = velocity H = total head Ps = the power supplied to the pump Z = height above the datum plane P: = the power delivered to the fluid

Jun 11, 2022
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