5.3.31 Question Help ▼ In a survey of women in a certain country (ages 20 - 29), the mean height was 62.5 inches with a standard deviation of 2.68 inches. Answer the following questions about the...


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5.3.31<br>Question Help ▼<br>In a survey of women in a certain country (ages 20 - 29), the mean height was 62.5 inches with a standard deviation of 2.68 inches. Answer the following questions about the specified normal distribution.<br>(a) What height represents the 95th percentile?<br>(b) What height represents the first quartile?<br>Click to view page 1 of the table. Click to view page 2 of the table.<br>(a) The height that represents the 95th percentile is<br>(Round to two decimal places as needed.)<br>inches.<br>

Extracted text: 5.3.31 Question Help ▼ In a survey of women in a certain country (ages 20 - 29), the mean height was 62.5 inches with a standard deviation of 2.68 inches. Answer the following questions about the specified normal distribution. (a) What height represents the 95th percentile? (b) What height represents the first quartile? Click to view page 1 of the table. Click to view page 2 of the table. (a) The height that represents the 95th percentile is (Round to two decimal places as needed.) inches.
Find the indicated z-scores shown in the graph.<br>Click to view page 1 of the table.<br>Click to view page 2 of the table.<br>0.0329<br>0.0329<br>X<br>z=? Ó z=?<br>The z-scores are<br>(Use a comma to separate answers as needed. Round to two decimal places as needed.)<br>

Extracted text: Find the indicated z-scores shown in the graph. Click to view page 1 of the table. Click to view page 2 of the table. 0.0329 0.0329 X z=? Ó z=? The z-scores are (Use a comma to separate answers as needed. Round to two decimal places as needed.)

Jun 08, 2022
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