4 5 of 5 Question 4 4. (a) Assume T > 0, and that the moment generating function Mx (t) of a random variable X is finite for t

45 of 5<br>Question 4<br>4. (a) Assume T > 0, and that the moment generating function Mx (t) of a random variable X is finite for t < T. Explain<br>the expansion<br>Mx (t) = 1+ ut +s?t² + o(t³),<br>2<br>%3|<br>where u =<br>E(X) and s2<br>E(X²). [You may assume the validity of interchanging expectation and differentiation.]<br>(b) Let X, Y be independent, identically distributed random variables with mean 0 and variance 1, and assume their<br>moment generating function M satisfies the condition of part (a) with T = o. Suppose that X +Y and X - Y are<br>independent.<br>(i) Using M(2t) deduce that (t) := M(t)/M(-t) satisfies (t) = »(t/2)². Clearly state any property of the<br>moment generating functions you use.<br>(ii) Show that b(h)<br>= 1+ o(h?) as h → 0, and deduce that (t)<br>= 1 for all t.<br>(iii) Show that X and Y are normally distributed.<br>国<br>

Extracted text: 5 of 5 Question 4 4. (a) Assume T > 0, and that the moment generating function Mx (t) of a random variable X is finite for t < t.="" explain="" the="" expansion="" mx="" (t)="1+" ut="" +s?t²="" +="" o(t³),="" 2="" %3|="" where="" u="E(X)" and="" s2="" e(x²).="" [you="" may="" assume="" the="" validity="" of="" interchanging="" expectation="" and="" differentiation.]="" (b)="" let="" x,="" y="" be="" independent,="" identically="" distributed="" random="" variables="" with="" mean="" 0="" and="" variance="" 1,="" and="" assume="" their="" moment="" generating="" function="" m="" satisfies="" the="" condition="" of="" part="" (a)="" with="" t="o." suppose="" that="" x="" +y="" and="" x="" -="" y="" are="" independent.="" (i)="" using="" m(2t)="" deduce="" that="" (t)="" :="M(t)/M(-t)" satisfies="" (t)="»(t/2)²." clearly="" state="" any="" property="" of="" the="" moment="" generating="" functions="" you="" use.="" (ii)="" show="" that="" b(h)="1+" o(h?)="" as="" h="" →="" 0,="" and="" deduce="" that="" (t)="1" for="" all="" t.="" (iii)="" show="" that="" x="" and="" y="" are="" normally="" distributed.="">

Jun 01, 2022
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