Please explain step by step (see attached photo) process on finding the running time in Big Oh notation and showing that Master Theorem has proved the answer. The answer is already correct only...

Please explain step by step
(see attached photo)
process on finding the
running time in Big Oh notation and showing that Master Theorem has proved the answer.
The answer is already correct only explanation needed.

5 int foo 5 Lint nE<br>inti,j, sum =0;<br>Bare Case<br>TO) OLi)-1<br>Reunsive Case<br>Oln) + T(%)<br>TOn) = n° + T(2) 1<br>Ti) = n+ ()+T(%')<br>Tul = 5 (+T(%) =<br>Ten) -<br>retin ,<br>O(n°)<br>For (i-1; i<an'3; i 2){<br>5n<br>= ?n?<br>+T(%) ing<br>T)- +()+TC%) =<br>in general<br>Tn)-(2i+1)nT(

Extracted text: 5 int foo 5 Lint nE inti,j, sum =0; Bare Case TO) OLi)-1 Reunsive Case Oln) + T(%) TOn) = n° + T(2) 1 Ti) = n+ ()+T(%') Tul = 5 (+T(%) = Ten) - retin , O(n°) For (i-1; i

Jun 10, 2022

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Please explain step by step (see attached photo) process on finding the running time in Big Oh notation and showing that Master Theorem has proved the answer. The answer is already correct only...

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