5. For a lowpass signal with a bandwidth of 6000HZ, what is the minimum sampling frequency for perfect reconstruction of the signal? What is the minimum required sampling frequency if a guard band of...


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5. For a lowpass signal with a bandwidth of 6000HZ, what is the minimum<br>sampling frequency for perfect reconstruction of the signal? What is the minimum<br>required sampling frequency if a guard band of 2000 Hz is required? If the<br>reconstruction filter has the frequency response<br>´K<br>Ifl < 7000<br>H(f) =<br>Ifl – 7000<br>К — К<br>7000 < |f| < 10,000<br>3000<br>otherwise<br>Answer: -<br>For no aliasing to occur we must sample at the Nyquist rate fs = 2 · 6000 samples/sec<br>= 12000 samples/sec With a guard band of 2000 fs – 2W = 2000 ==fs = 14000 The<br>reconstruction filter should not pick-up frequencies of the images of the spectrum<br>X(f). The nearest image spectrum is centered at fs and occupies the frequency band<br>[fs – W, fs + W 1. Thus the highest frequency of the reconstruction filter (= 10000)<br>should satisfy 10000 <fs – W==fs >16000 For the value fs = 16000, K should be<br>such that K · fs = 1 ==K = 1/(16000)<br>

Extracted text: 5. For a lowpass signal with a bandwidth of 6000HZ, what is the minimum sampling frequency for perfect reconstruction of the signal? What is the minimum required sampling frequency if a guard band of 2000 Hz is required? If the reconstruction filter has the frequency response ´K Ifl < 7000="" h(f)="Ifl" –="" 7000="" к="" —="" к="" 7000="">< |f|="">< 10,000="" 3000="" otherwise="" answer:="" -="" for="" no="" aliasing="" to="" occur="" we="" must="" sample="" at="" the="" nyquist="" rate="" fs="2" ·="" 6000="" samples/sec="12000" samples/sec="" with="" a="" guard="" band="" of="" 2000="" fs="" –="" 2w="2000" =="fs" =="" 14000="" the="" reconstruction="" filter="" should="" not="" pick-up="" frequencies="" of="" the="" images="" of="" the="" spectrum="" x(f).="" the="" nearest="" image="" spectrum="" is="" centered="" at="" fs="" and="" occupies="" the="" frequency="" band="" [fs="" –="" w,="" fs="" +="" w="" 1.="" thus="" the="" highest="" frequency="" of="" the="" reconstruction="" filter="" (="10000)" should="" satisfy="" 10000="">16000 For the value fs = 16000, K should be such that K · fs = 1 ==K = 1/(16000)

Jun 10, 2022
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