4:10 Expianation Given information: The stress component along x direction as 150 MPа. The stress component along y direction as Oy = 30 MPa The shear stress component as 'æy = -80 MPa Calculation:...

Where did-53.13 and -26.6 and 63.4 come from please show the work

Extracted text: 4:10 Expianation Given information: The stress component along x direction as 150 MPа. The stress component along y direction as Oy = 30 MPa The shear stress component as 'æy = -80 MPa Calculation: Calculate the principal plane (0,) as shown below. 2Tzy tan (20,) Substitute 150 MPa for Jx, 30 MPa for Cy, and -80 MPa for Txy. 2x(-80) tan (20,) 150-30 tan (20,) = –1.333 20, = -26.6° and 63.4° = -53.13° Op Hence, the principal planes of the state of stress is -26.6° and 63.4° To determine The principal stresses of the state of stress. Answer