Redraw the Norton Equivalent circuit for Thevenin Equivalent Circuit using a previous problem that was solved and calculate the load current (?? ) dropped across the load resistor (?? )? NOTE...


Redraw the Norton Equivalent circuit for Thevenin Equivalent Circuit using a previous problem that was solved and calculate the load current (?? ) dropped across the load resistor (?? )?


NOTE (backround information): for this example and the circuit you see below we were asked to perform Thevenins equivalent circuit. We were asked to find...


Rth, Eth,
and IL the anwers I got were


Rth= 1 kΩ


Eth= 3 V


IL= 0.273 mA



4 kf<br>4 kn<br>20 V<br>4 kN<br>10 kn<br>8 mA<br>4 k<br>

Extracted text: 4 kf 4 kn 20 V 4 kN 10 kn 8 mA 4 k

Jun 11, 2022
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