Redraw the Norton Equivalent circuit for Thevenin Equivalent Circuit using a previous problem that was solved and calculate the load current (?? ) dropped across the load resistor (?? )?
NOTE (backround information): for this example and the circuit you see below we were asked to perform Thevenins equivalent circuit. We were asked to find...
Rth, Eth,and IL the anwers I got were
Rth= 1 kΩ
Eth= 3 V
IL= 0.273 mA
Extracted text: 4 kf 4 kn 20 V 4 kN 10 kn 8 mA 4 k
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