Redraw the Norton Equivalent circuit for Thevenin Equivalent Circuit using a previous problem that was solved and calculate the load current (IL ) dropped across the load resistor (RL)? NOTE...

Redraw the Norton Equivalent circuit for Thevenin Equivalent Circuit using a previous problem that was solved and calculate the load current (I_L
) dropped across the load resistor (R_L)?

NOTE (backround information): for this example and the circuit you see below we were asked to perform Thevenins equivalent circuit. We were asked to find...

R_th, E_th, and I_L the anwers I got were

R_th= 1 kΩ

E_th= 3 V

I_L= 0.273 mA

Extracted text: 4 kf 4 kn 20 V 4 kN 10 kn 8 mA 4 k