4. Find the convolution of $f(t)=\left\{\begin{array}{11}\frac{3}{2} t, & 0 \leqt \leq 3 \ 0, & \text { otherwise }\end{array}\right.$ and Sg(t)=\left\{\begin{array}{i1}4, & -i leg i \leg 3' e, &...

$4. Find the convolution of $f(t)=\left\{\begin{array}{11}\frac{3}{2} t, & 0 \leqt \leq 3 \ 0, & \text { otherwise }\end{array}\right.$ and Sg(t)=\left\{\begin{array}{i1}4, & -i leg i \leg 3' e, & \text { otherwise }\end{array}\right. $ Answer: $$ f* g=\left\{\begin{array}{11} 0 & t \leqslant-1 \ \frac{4}{3}(t+1)^[2} & -1<t \leqslant 2 W 12 & 2<t \leqslant 3 \ 12-\frac{4}{3}(t-3)*(2} & 3<t \leqslant 6 \ O & t>6 \end{array}\right. $$ SP. SD. 330| $

Extracted text: 4. Find the convolution of $f(t)=\left\{\begin{array}{11}\frac{3}{2} t, & 0 \leqt \leq 3 \ 0, & \text { otherwise }\end{array}\right.$ and Sg(t)=\left\{\begin{array}{i1}4, & -i leg i \leg 3' e, & \text { otherwise }\end{array}\right. $ Answer: $$ f* g=\left\{\begin{array}{11} 0 & t \leqslant-1 \ \frac{4}{3}(t+1)^[2} & -16 \end{array}\right. $$ SP. SD. 330|

Jun 11, 2022

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4. Find the convolution of $f(t)=\left\{\begin{array}{11}\frac{3}{2} t, & 0 \leqt \leq 3 \ 0, & \text { otherwise }\end{array}\right.$ and Sg(t)=\left\{\begin{array}{i1}4, & -i leg i \leg 3' e, &...

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