(3) We continue with A and RREF(A) from the previous question. (a) Give a basis for the null space of A. 12 1 13 -1|. Give a parametrization for the set of solutions i to the 26 (b) It turns out that...

(3) We continue with A and RREF(A) from the previous question.<br>(a) Give a basis for the null space of A.<br>12<br>1<br>13<br>-1|. Give a parametrization for the set of solutions i to the<br>26<br>(b) It turns out that A 1<br>-17<br>12<br>13<br>equation A · 7 =<br>-1<br>26<br>-17<br>

Extracted text: (3) We continue with A and RREF(A) from the previous question. (a) Give a basis for the null space of A. 12 1 13 -1|. Give a parametrization for the set of solutions i to the 26 (b) It turns out that A 1 -17 12 13 equation A · 7 = -1 26 -17
[1 0 6 0 -7 0 1 -8 0 0 1 5 4 -2 4 2 1 4 2 4 RREF(A) 0 0 0 0 A = 4 3 2 -10 9. 3 2 4 15 0 0 -1 1 -14 –1 -2 0 0 0 0

[1 0<br>6 0 -7<br>0 1 -8 0<br>0 1<br>5 4<br>-2<br>4<br>2 1<br>4<br>2<br>4<br>RREF(A)<br>0 0<br>0 0<br>A =<br>4 3<br>2 -10<br>9.<br>3 2<br>4<br>15<br>0 0<br>-1 1 -14 –1<br>-2<br>0 0<br>0 0<br>

Extracted text: [1 0 6 0 -7 0 1 -8 0 0 1 5 4 -2 4 2 1 4 2 4 RREF(A) 0 0 0 0 A = 4 3 2 -10 9. 3 2 4 15 0 0 -1 1 -14 –1 -2 0 0 0 0

Jun 03, 2022

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(3) We continue with A and RREF(A) from the previous question. (a) Give a basis for the null space of A. 12 1 13 -1|. Give a parametrization for the set of solutions i to the 26 (b) It turns out that...

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