3. Consider the function f(t) = 2t2 – 3t + 7 on the interval -1

please send correct solution for Q 3 Using Demos Graphing
3. Consider the function f(t) = 2t2 – 3t + 7 on the interval -1 < t < 1 with<br>periodicity P = 2<br>• Give a Fourier series representation of f<br>• Using graphing software, plot a graph showing the first 10 Fourier<br>components and f(t) on the interval -1 < t< 1<br>

Extracted text: 3. Consider the function f(t) = 2t2 – 3t + 7 on the interval -1 < t="">< 1="" with="" periodicity="" p="2" •="" give="" a="" fourier="" series="" representation="" of="" f="" •="" using="" graphing="" software,="" plot="" a="" graph="" showing="" the="" first="" 10="" fourier="" components="" and="" f(t)="" on="" the="" interval="" -1=""><><>
46%<br>O {-15xS12-3x +7}<br>{-1srsı- cos(mv) + cos(2mv) - cos(3ar) - sin(xr) - sia( 2xr) sin( 3zr))<br>V (-1sxs1:- cos (ns)+ cos(2nx)- cos (3ax) + cos(dz«) – sin(1s) + sin( 2ar)- sin(3a)-<br>V (-15xs1 - cos (m) + cos(2ax)- cos(3zx)+ cos(szr)- cos(Szr)- sin(zx) + sin(20<br>16<br>

Extracted text: 46% O {-15xS12-3x +7} {-1srsı- cos(mv) + cos(2mv) - cos(3ar) - sin(xr) - sia( 2xr) sin( 3zr)) V (-1sxs1:- cos (ns)+ cos(2nx)- cos (3ax) + cos(dz«) – sin(1s) + sin( 2ar)- sin(3a)- V (-15xs1 - cos (m) + cos(2ax)- cos(3zx)+ cos(szr)- cos(Szr)- sin(zx) + sin(20 16

Jun 04, 2022
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