24. Suppose that I choose six of the first ten positive integers. Prove that I must have chosen two numbers such that one is a divisor of the other. [HINT: Write each of the 10 numbers as a power of 2...

24. Suppose that I choose six of the first ten positive integers. Prove that I must have chosen<br>two numbers such that one is a divisor of the other. [HINT: Write each of the 10 numbers<br>as a power of 2 multiplied by an odd number, then use the pigeonhole principle.]<br>

Extracted text: 24. Suppose that I choose six of the first ten positive integers. Prove that I must have chosen two numbers such that one is a divisor of the other. [HINT: Write each of the 10 numbers as a power of 2 multiplied by an odd number, then use the pigeonhole principle.]

Jun 05, 2022

SOLUTION.PDF

24. Suppose that I choose six of the first ten positive integers. Prove that I must have chosen two numbers such that one is a divisor of the other. [HINT: Write each of the 10 numbers as a power of 2...

Get Answer To This Question

Related Questions & Answers

Submit New Assignment