24. Initially, a tank contains 400 L of water with 10 kg of salt in solution. Water containing 0.1 kg of salt per liter (L) is entering at a rate of 1 L/min, and the mixture is allowed to flow out of...


24. Initially, a tank contains 400 L of water with 10 kg of salt in solution. Water containing<br>0.1 kg of salt per liter (L) is entering at a rate of 1 L/min, and the mixture is allowed<br>to flow out of the tank at a rate of 2 L/min. Let Q(t) be the amount of salt at time<br>t measured in kilograms. What is the right formulation of the differential equation for<br>Q(t)?<br>O dQ<br>2Q(t)<br>0.1<br>dt<br>400 + t<br>O dQ<br>= 0.1<br>2Q(t)<br>dt<br>400 – t<br>-<br>dQ<br>10<br>2Q(t)<br>dt<br>400<br>400 +t<br>dQ<br>2Q(t)<br>= 0.1<br>-<br>dt<br>400<br>2Q(t)<br>400 – t<br>O dQ<br>0.1<br>dt<br>400<br>-<br>

Extracted text: 24. Initially, a tank contains 400 L of water with 10 kg of salt in solution. Water containing 0.1 kg of salt per liter (L) is entering at a rate of 1 L/min, and the mixture is allowed to flow out of the tank at a rate of 2 L/min. Let Q(t) be the amount of salt at time t measured in kilograms. What is the right formulation of the differential equation for Q(t)? O dQ 2Q(t) 0.1 dt 400 + t O dQ = 0.1 2Q(t) dt 400 – t - dQ 10 2Q(t) dt 400 400 +t dQ 2Q(t) = 0.1 - dt 400 2Q(t) 400 – t O dQ 0.1 dt 400 -

Jun 05, 2022
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