2) Two parallel-plate capacitors are constructed using dielectric materials with dielectric constants K, = 3 and K, = 5, as shown in Figure. Parallel-plates have the area A = 0.7 m². The distance is d...


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2) Two parallel-plate capacitors are constructed using dielectric materials with dielectric constants<br>K, = 3 and K, = 5, as shown in Figure. Parallel-plates have the area A = 0.7 m². The distance is<br>d = 0.05 m. A potential difference of AV = 24 V is applied to the circuit.<br>(a) Find the equivalent capacitance of the system.<br>(b) Find the potential AV1. (8=8.85×10-12 C²/N×m²)<br>K1<br>A/2<br>AV1<br>K2<br>A/2<br>A<br>d<br>K2<br>K1<br>A/2<br>2d/3 d/3<br>K2<br>A/2<br>d<br>AV = 24 V<br>

Extracted text: 2) Two parallel-plate capacitors are constructed using dielectric materials with dielectric constants K, = 3 and K, = 5, as shown in Figure. Parallel-plates have the area A = 0.7 m². The distance is d = 0.05 m. A potential difference of AV = 24 V is applied to the circuit. (a) Find the equivalent capacitance of the system. (b) Find the potential AV1. (8=8.85×10-12 C²/N×m²) K1 A/2 AV1 K2 A/2 A d K2 K1 A/2 2d/3 d/3 K2 A/2 d AV = 24 V

Jun 10, 2022
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